x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式

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x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式
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x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式
x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式

x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4如何分解因式
原式=(x+2)/(x+1)-(x+3)/(x+2)-（x-4)/(x-3)+(x-5)/(x-4)
=[(x+2)*(x+2)-(x+3)*（x+1）]/(x+1)*(x+2)--[(x-4)*(x-4)-(x-3)*(x-5)]/(x-3)*(x-4)
=1/(x+1)*(x+2)-1/(x-3)*(x-4)
=[(x-3)*(x-4)-(x+1)*(x+2)]/[(x+1)*(x+2)*(x-3)*(x-4)]
=10(1-x)/[(x+1)*(x+2)*(x-3)*(x-4)]

-x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4
=-4/X-4=-4(1+1/X)

扬帆知道快乐10(x^2+2x+3)/[(x+1)(x+2)(x-3)(x-4)].

x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4
解:
原式=[1+ 1/(x+1)] - [1+ 1/(x+2)] - [1- 1/(x-3)] +[1- 1/(x-4)]
= 1/(x+1) -1/(x+2) +1/(x-3) -1/(x-4)
=[(x+2)-(x+1)] /[(x+1)(x+2)] +[(x-4)-(x-3)] /[(x-3)(...

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x+2/x+1-x+3/x+2-x-4/x-3+x-5/x-4
解:
原式=[1+ 1/(x+1)] - [1+ 1/(x+2)] - [1- 1/(x-3)] +[1- 1/(x-4)]
= 1/(x+1) -1/(x+2) +1/(x-3) -1/(x-4)
=[(x+2)-(x+1)] /[(x+1)(x+2)] +[(x-4)-(x-3)] /[(x-3)(x-4)]
=1/[(x+1)(x+2)] - 1/[(x-3)(x-4)]
=([(x-3)(x-4)) -[(x+1)(x+2)]) /[(x+1)(x+2)(x-3)(x-4)]
=[(x^2 -7x+12) -[x^2+3x+2)]/[(x+1)(x+2)(x-3)(x-4)]
= (-10x+10)/[(x+1)(x+2)(x-3)(x-4)]
=10(1-x)/[(x+1)(x+2)(x-3)(x-4)]
我刚做过过这道题。。。。

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