已知(3x-2y)^2-10(3x-2y)+25=0,求9x^2-12xy+4y^2+1的值.
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已知(3x-2y)^2-10(3x-2y)+25=0,求9x^2-12xy+4y^2+1的值.
已知(3x-2y)^2-10(3x-2y)+25=0,求9x^2-12xy+4y^2+1的值.
已知(3x-2y)^2-10(3x-2y)+25=0,求9x^2-12xy+4y^2+1的值.
(3x-2y)^2-10(3x-2y)+25=0,
(3x-2y-5)^2=0
所以
3x-2y-5=0
3x-2y=5
9x^2-12xy+4y^2+1
=(3x-2y)^2+1
=25+1
=26
3x-2y=t => t^2-10t+25=0=(t-5)^2 => t=5
9x^2-12xy+4y^2+1=[(3x)^2 -2(3x)(2y)+(2y)^2]+1=[3x-2y]^2 +1=t^2 +1 =25+1=26
所求式子= (3x-2y)^2 加 1 所以令3x - 2y = m 代入已知式子就行了
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