解不等式:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^n,不好意思,不等式打错了,应该是:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^(n+1)

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解不等式:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^n,不好意思,不等式打错了,应该是:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^(n+1)
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解不等式:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^n,不好意思,不等式打错了,应该是:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^(n+1)
解不等式:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^n,
不好意思,不等式打错了,应该是:
[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^(n+1)

解不等式:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^n,不好意思,不等式打错了,应该是:[n/(n+1)]﹙3/4﹚^n≥[﹙n+1﹚/﹙n+2﹚](3/4)^(n+1)

两边除以(3/4)^n
n/(n+1)-(n+1)/(n+2)>=0
(n²+2n-n²-2n-1)/(n+1)(n+2)≥0
-1/(n+1)(n+2)≥0
所以(n+1)(n+2)<0
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