已知圆M:x的平方+(y-2)的平方=1,Q是X轴上的动点.若QA与QB分别与圆M相切与A,B两点,且AB的绝对值=三分之四倍根号2 .求直线MQ的方程
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![已知圆M:x的平方+(y-2)的平方=1,Q是X轴上的动点.若QA与QB分别与圆M相切与A,B两点,且AB的绝对值=三分之四倍根号2 .求直线MQ的方程](/uploads/image/z/6930612-36-2.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86M%3Ax%E7%9A%84%E5%B9%B3%E6%96%B9%2B%28y-2%29%E7%9A%84%E5%B9%B3%E6%96%B9%3D1%2CQ%E6%98%AFX%E8%BD%B4%E4%B8%8A%E7%9A%84%E5%8A%A8%E7%82%B9.%E8%8B%A5QA%E4%B8%8EQB%E5%88%86%E5%88%AB%E4%B8%8E%E5%9C%86M%E7%9B%B8%E5%88%87%E4%B8%8EA%2CB%E4%B8%A4%E7%82%B9%2C%E4%B8%94AB%E7%9A%84%E7%BB%9D%E5%AF%B9%E5%80%BC%3D%E4%B8%89%E5%88%86%E4%B9%8B%E5%9B%9B%E5%80%8D%E6%A0%B9%E5%8F%B72+.%E6%B1%82%E7%9B%B4%E7%BA%BFMQ%E7%9A%84%E6%96%B9%E7%A8%8B)
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