∫上限π/2,下限-π/2(cosx+x)dx=
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∫上限π/2,下限-π/2(cosx+x)dx=
∫上限π/2,下限-π/2(cosx+x)dx=
∫上限π/2,下限-π/2(cosx+x)dx=
cosx的原函数是sinx,
x的原函数是0.5x²
所以
定积分
∫(上限π/2,下限-π/2) cosx+x dx
= sinx +0.5x² 代入上下限π/2和 -π/2
=sin(π/2) +0.5(π/2)² -sin(-π/2) -0.5(π/2)²
=1+1
=2
∫上限π/2,下限-π/2(cosx+x)dx=
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