∫上限π/2,下限-π/2(cosx+x)dx=

∫上限π/2,下限-π/2(cosx+x)dx= ∫(lnx-1)dx/x^2∫(下限0,上限π/2)cosxdx/(cosx+sinx) 求定积分[上限π,下限0]∫(x^2)sgn(cosx)dx ∫ [上限π,下限0] |cosx| dx ∫(1+x^3)cosx/1+sin^2 xdx 积分上限为π/2 下限为-π/2 求定积分∫上限π/2下限-π/2 (1+x)cosx/1+cos^2xdx ∫(1+x^3)cosx/1+sin^2 xdx 积分上限为π/2 下限为-π/2 ∫(1+x)sinxdx上限π/2,下限0 ∫(上限π/2,下限0)(∫(上限π/2 ,下限x)siny/2 dy)dx错了哦 应该是 ∫(上限π/2,下限0)(∫(上限π/2 ,下限x)siny/y dy)dx 求定积分下限∫-π/2到上限π/2sinx/(2+cosx)dx 计算定积分 ∫(2sinx-3cosx)dx(上限17π/3 下限π/3) 急.∫√[1-(cosx)^2]dx ,上限是π,下限是-π ,求结果 d/dx∫(上限cosx下限sinx)cos(πt^2)dt 求导数 求定积分(下限0,上限π/4)∫(1/(1+(cosx)^2))dx 定积分∫上限π/2下限0 sinx/(sinx+cosx)dx d/dx∫(上限cosx下限sinx)cos(πt^2)dt 求导数 ∫1/(sinx+cosx)dx上限π/2下限0用万能公式怎么做, ∫上限π/2 下限0 e^sinx cosx dx=