x^2+4y^2-2xy+12y+12=0,求x^y的值

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x^2+4y^2-2xy+12y+12=0,求x^y的值
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x^2+4y^2-2xy+12y+12=0,求x^y的值
x^2+4y^2-2xy+12y+12=0,求x^y的值

x^2+4y^2-2xy+12y+12=0,求x^y的值
x^2+4y^2-2xy+12y+12
=x^2-2xy+y^2+3(y^2+4y+4)
=(x-y)^2+3(y+2)^2
=0
所以：x-y=0,y-2=0
即x=y=-2
则x^y=(-2)^(-2)=1/(-2)^2=1/4

(x-y)²+3(y+2)²=0，x=y，y=-2，x^y=1/4.

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