已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-...已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-(-1)∧n×an,不等式Ck≥2014(1≤k≤100,k∈N*)的

已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-...已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-(-1)∧n×an,不等式Ck≥2014(1≤k≤100,k∈N*)的
已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-...
已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-(-1)∧n×an,不等式Ck≥2014(1≤k≤100,k∈N*)的解集为M求所有dk+ak(k∈M)的和. 哪位大神帮帮忙,我算了半天,才算出an的通项公式为an＝2∧n
D(k)是一个数列

已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-...已知等比数列an为递增数列,且A5²＝A10,2(An+An+2)＝5An+1.n属于N＊.⑴令Cn=1-(-1)∧n×an,不等式Ck≥2014(1≤k≤100,k∈N*)的
dk+ak中dk是?