如图,在梯形ABCD中,AD∥BC,E为CD的中点,AE平分∠BAD.①求证:BE平分∠ABC②求证:AB=AD+BC
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![如图,在梯形ABCD中,AD∥BC,E为CD的中点,AE平分∠BAD.①求证:BE平分∠ABC②求证:AB=AD+BC](/uploads/image/z/6943998-30-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%88%A5BC%2CE%E4%B8%BACD%E7%9A%84%E4%B8%AD%E7%82%B9%2CAE%E5%B9%B3%E5%88%86%E2%88%A0BAD.%E2%91%A0%E6%B1%82%E8%AF%81%EF%BC%9ABE%E5%B9%B3%E5%88%86%E2%88%A0ABC%E2%91%A1%E6%B1%82%E8%AF%81%EF%BC%9AAB%3DAD%2BBC)
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