¥%¥#%¥……%¥、、(~o zZ①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)②-2^3-3×(-1)^3-(-1)^4③-2×(0.1)^3×(-0.2)^2+(-0.8)

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 18:41:06
¥%¥#%¥……%¥、、(~o zZ①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)②-2^3-3×(-1)^3-(-1)^4③-2×(0.1)^3×(-0.2)^2+(-0.8)
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¥%¥#%¥……%¥、、(~o zZ①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)②-2^3-3×(-1)^3-(-1)^4③-2×(0.1)^3×(-0.2)^2+(-0.8)
¥%¥#%¥……%¥、、(~o zZ
①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)
②-2^3-3×(-1)^3-(-1)^4
③-2×(0.1)^3×(-0.2)^2+(-0.8)

¥%¥#%¥……%¥、、(~o zZ①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)②-2^3-3×(-1)^3-(-1)^4③-2×(0.1)^3×(-0.2)^2+(-0.8)
①(-13又3分之1)÷(-5)+(-6又3分之2)÷(-5)
=-(40/3)÷(-5)+(-20/3)÷(-5)
=(40/3)÷5+(20/3)÷5
=8/3+4/3
=12/3
=4
②-2^3-3×(-1)^3-(-1)^4
=-8-3×(-1)-1
=-8+3-1
=-5-1
=-6
③-2×(0.1)^3×(-0.2)^2+(-0.8)
=-2×0.001×0.04-0.8
=-0.00008-0.8
=-0.80008

1、原式=-(40/3)÷(-5)+(-20/3)÷(-5)
=(40/3)÷5+(20/3)÷5
=(40/3+20/3)÷5
=20÷5
=4
2、原式=-8-3×(-1)-1
=-8+3-1
=-5-1
=-6
3、原式=-2×0.001×0.04-0.8
=-0.00008-0.8
=-0.80008