关于x的二次方程ax²﹣2x+1两根满足0<x1<1<x2<2,求a的取值范围是方程ax²﹣2x+a+1=0 刚刚打错了
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![关于x的二次方程ax²﹣2x+1两根满足0<x1<1<x2<2,求a的取值范围是方程ax²﹣2x+a+1=0 刚刚打错了](/uploads/image/z/6948902-38-2.jpg?t=%E5%85%B3%E4%BA%8Ex%E7%9A%84%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8Bax%26%23178%3B%EF%B9%A32x%EF%BC%8B1%E4%B8%A4%E6%A0%B9%E6%BB%A1%E8%B6%B30%EF%BC%9Cx1%EF%BC%9C1%EF%BC%9Cx2%EF%BC%9C2%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E6%98%AF%E6%96%B9%E7%A8%8Bax%26%23178%3B%EF%B9%A32x%EF%BC%8Ba%EF%BC%8B1%EF%BC%9D0+%E5%88%9A%E5%88%9A%E6%89%93%E9%94%99%E4%BA%86)
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