3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 14:16:01
3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于
x)33ԍ65`MX۞X[akSiko|m]}6IEi/ΧO{=_נƦ {nQS64F7* 6PCnE%Vu@e&epUX**5@º'ohPXO[B$?ӏt *M 1]C)eb_\g D0QV@K%O<5Ɏ]̂XI0°&o )>@qluM qzs12ҨLw2xsD

3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于
3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于

3x^2y-[2xy-2(xy-2/3x^2y)+xy],其中x=3,y=-3/1.等于
先化简,再求值
3x²y-[2xy-2(xy-2/3x²y)+xy]
=3x²y-2xy+2(xy-2/3x²y)-xy
=3x²y-2xy+2xy-4/3x²y-xy
=5/3x²y-xy
=xy(5/3x-1)
将x=3,y=-1/3 代入
原式=xy(5/3x-1)=3×(-1/3)(5/3×3-1)=-1×(5-1)=-4

∵x=3,y=-3/1(此处应为:y=-1/3)
3x^2y-[2xy-2(xy-2/3x^2y)+xy]=3x²y-2xy+2xy-4x²y/3-xy=5x²y/3-xy=5×3²×(-1/3)/3-3×(-1/3)=-5+1=-4

3x²y-[2xy-2(xy-2/3x²y)+xy]
=3x²y﹣3x²y﹣xy
=﹣xy
=﹣3×﹙﹣1/3﹚
=1