二元二元一次解方程:(1)3x²-1=0 (2)x(2x+3)=5(2x+3)(3)x²-4x-2=0 (4)2x²-5x+1=0
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![二元二元一次解方程:(1)3x²-1=0 (2)x(2x+3)=5(2x+3)(3)x²-4x-2=0 (4)2x²-5x+1=0](/uploads/image/z/696020-68-0.jpg?t=%E4%BA%8C%E5%85%83%E4%BA%8C%E5%85%83%E4%B8%80%E6%AC%A1%E8%A7%A3%E6%96%B9%E7%A8%8B%EF%BC%9A%EF%BC%881%EF%BC%893x%26%23178%3B-1%3D0+%EF%BC%882%EF%BC%89x%EF%BC%882x%2B3%29%3D5%EF%BC%882x%2B3%29%EF%BC%883%EF%BC%89x%26%23178%3B-4x-2%3D0+%284%292x%26%23178%3B-5x%2B1%3D0)
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二元二元一次解方程:(1)3x²-1=0 (2)x(2x+3)=5(2x+3)(3)x²-4x-2=0 (4)2x²-5x+1=0
二元二元一次解方程:(1)3x²-1=0 (2)x(2x+3)=5(2x+3)(3)x²-4x-2=0 (4)2x²-5x+1=0
二元二元一次解方程:(1)3x²-1=0 (2)x(2x+3)=5(2x+3)(3)x²-4x-2=0 (4)2x²-5x+1=0
(1)3x²-1=0
x^2=1/3
x=±根号1/3
(2)x(2x+3)=5(2x+3)
2x^2+3x-10x-15=0
2x^2-7x-15=0
(x-5)(2x+3)=0
(x-5)=0
x=5
(2x+3)=0
x=-3/2
(3)x²-4x-2=0
x²-4x+4=6
(x-2)^2=6
x-2=±根号6
x=2±根号6
(4)2x²-5x+1=0
2(x^2-5/2x+25/16)+1-25/8=0
2(x^2-5/2x+25/16)-17/8=0
2(x-5/4)^2=17/8
(x-5/4)^2=17/16
x-5/4=±√(17)/4
x=5/4±√(17)/4