如图,抛物线y=-(x-1)²+4交x正半轴于点A,交y轴于点E,B为抛物线的顶点连接AB、AE、BE.
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/05 03:31:31
![如图,抛物线y=-(x-1)²+4交x正半轴于点A,交y轴于点E,B为抛物线的顶点连接AB、AE、BE.](/uploads/image/z/6962220-36-0.jpg?t=%E5%A6%82%E5%9B%BE%2C%E6%8A%9B%E7%89%A9%E7%BA%BFy%3D-%28x-1%EF%BC%89%26%23178%3B%2B4%E4%BA%A4x%E6%AD%A3%E5%8D%8A%E8%BD%B4%E4%BA%8E%E7%82%B9A%2C%E4%BA%A4y%E8%BD%B4%E4%BA%8E%E7%82%B9E%2CB%E4%B8%BA%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%9A%84%E9%A1%B6%E7%82%B9%E8%BF%9E%E6%8E%A5AB%E3%80%81AE%E3%80%81BE.)
xRNA~`J_K&0ӥU+[c"RH,
фh[iy-W3[^
W$;;;s7|gޛǵ.Uj}ZRb9YqJw^:v՟o%,
aQf{H\8AO^T?L%9JLSHse<~1gPƳ}ely'k9Iϰϲ9S˳Ow[urӳ
DxQBB\ao`eYY3yAC ԠK nҰY@2'#zMJ\^ZPF N%PdH%CKBcGy[R n0w?zyW^_ !I<~ ]त`OA=\-ܩ+(wa0(Ebȅ 0im3WYxZՍW.oͥ^wRûDU>G`9?c\~|Fulmv0D Bp-[@?'oB8Ħ}v;}
5}ViKӡtpuPMqRMH7Р0
(C(Z4+hIɿ7O
如图,抛物线y=-(x-1)²+4交x正半轴于点A,交y轴于点E,B为抛物线的顶点连接AB、AE、BE.
如图,抛物线y=-(x-1)²+4交x正半轴于点A,交y轴于点E,B为抛物线的顶点连接AB、AE、BE.
如图,抛物线y=-(x-1)²+4交x正半轴于点A,交y轴于点E,B为抛物线的顶点连接AB、AE、BE.
当y=0带入抛物线得x=3,x=-1(舍去)
A(3,0)
B(1,4)
当x=0带入抛物线
y=3
E(0,3)
S四边形=1/2(3+4)*1+1/2*2*4
=7/2+4
=15/2
*为乘,照抄即可!
呜呜呜我也初三辣,压力大的个B样
数学烂的个B样!
- from顾新玥
(1)由题意知A(3,0)B(1,4)E(0,3)过B点作BH⊥x轴于H,四边形的面积=梯形OEBH+△ABH的面积=1/2(3+4)*1+1/2*2*4=15/2
(2)s=1/2*3*3-1/2*(3-t)*(3-t)=-1/2(t-3)²+9/2