log4 8-log8 4=?
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log4 8-log8 4=?
log4 8-log8 4=?
log4 8-log8 4=?
log4 8
=log2^2 2^3
=log2 2^(3/2)
=3/2
所以:
log8 4=2/3;
所以:
log4 8-log8 4
=3/2-2/3
=5/6.
=log(2^2) (2^3)-log(2^3) (2^2)=3/2-2/3=9/6-4/6=5/6
log4 8-log8 4
=lg8/lg4-lg4/lg8
=lg(2^3)/lg(2^2)-lglg(2^2)/lg(2^3)
=3/2-2/3=5/6
3/2-2/3=5/6
log4 8-log8 4=?
log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的?
log3(4)·log4(8)·log8(m)=log4(16)则m=
设log3(4)*log4(8)*log8(m)=log4(16)那么m等于~
若log3 4*log4 8*log8 m=log4 16求m
log3 4*log4 8*log8 m=log4 16,则m为[ ]其中3、4、8、4为底数.
log3^4乘log4^8乘log8^m=log4^2麻烦过程写清楚一点.谢谢、
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