y=-1/2x²+2x-2(1)开口方向,对称轴顶点坐标.(2)设抛物线与x轴交于点B,与y轴交于A,求A,B坐标.如果以点A为顶点的抛物线经过点B,求抛物线解析式.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/30 22:13:17
![y=-1/2x²+2x-2(1)开口方向,对称轴顶点坐标.(2)设抛物线与x轴交于点B,与y轴交于A,求A,B坐标.如果以点A为顶点的抛物线经过点B,求抛物线解析式.](/uploads/image/z/6971552-8-2.jpg?t=y%3D-1%2F2x%26%23178%3B%2B2x-2%281%EF%BC%89%E5%BC%80%E5%8F%A3%E6%96%B9%E5%90%91%2C%E5%AF%B9%E7%A7%B0%E8%BD%B4%E9%A1%B6%E7%82%B9%E5%9D%90%E6%A0%87.%EF%BC%882%EF%BC%89%E8%AE%BE%E6%8A%9B%E7%89%A9%E7%BA%BF%E4%B8%8Ex%E8%BD%B4%E4%BA%A4%E4%BA%8E%E7%82%B9B%2C%E4%B8%8Ey%E8%BD%B4%E4%BA%A4%E4%BA%8EA%2C%E6%B1%82A%2CB%E5%9D%90%E6%A0%87.%E5%A6%82%E6%9E%9C%E4%BB%A5%E7%82%B9A%E4%B8%BA%E9%A1%B6%E7%82%B9%E7%9A%84%E6%8A%9B%E7%89%A9%E7%BA%BF%E7%BB%8F%E8%BF%87%E7%82%B9B%2C%E6%B1%82%E6%8A%9B%E7%89%A9%E7%BA%BF%E8%A7%A3%E6%9E%90%E5%BC%8F.)
xRN@-Ci%%i|!iw21(
"bDS¿`-͜{9L>kH$}sCIc$N
ѱ/FyƓϻw8"7M>v*xͺmx|uTy@ Qxꂀ<vOЩ`s؝Àϙ4Yd n5,}P0#䳙"4nl},o('H'`*TF`YHo*,`+#WT qR="
Yt7D3<8Q9Bldz>҃! e"C/=y\@Dh5Jt3X)ĶiyV
]H[Ue
y=-1/2x²+2x-2(1)开口方向,对称轴顶点坐标.(2)设抛物线与x轴交于点B,与y轴交于A,求A,B坐标.如果以点A为顶点的抛物线经过点B,求抛物线解析式.
y=-1/2x²+2x-2(1)开口方向,对称轴顶点坐标.
(2)设抛物线与x轴交于点B,与y轴交于A,求A,B坐标.
如果以点A为顶点的抛物线经过点B,求抛物线解析式.
y=-1/2x²+2x-2(1)开口方向,对称轴顶点坐标.(2)设抛物线与x轴交于点B,与y轴交于A,求A,B坐标.如果以点A为顶点的抛物线经过点B,求抛物线解析式.
(1)∵a=-½,∴开口向下
对称轴为x=-b/2a=4
顶点坐标(4,0)
(2)
∵顶点坐标为(4,0)
∴抛物线与x轴只有一个交点即顶点,∴B(4,0)
A点坐标为(0,-2)
设以A为顶点的抛物线为y=a(x-0)²-2
将B(4,0)代入解得
y'=½x²-2
开口向下,(2,0) A(0,—2) B(2,0)
x=(y-a)²+b x=(y+3/2)²-1/2