已知函数f(x)=x³+ax²+bx+c.过曲线y=f(x)上的点p(1.f(1))的切线方程为y=3x+1.若函数y=f(x)在区间[-2,1]上单调递增,求实数b的取值范围……用看对称轴解是啥意思来着……求详解给跪了
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![已知函数f(x)=x³+ax²+bx+c.过曲线y=f(x)上的点p(1.f(1))的切线方程为y=3x+1.若函数y=f(x)在区间[-2,1]上单调递增,求实数b的取值范围……用看对称轴解是啥意思来着……求详解给跪了](/uploads/image/z/6972443-35-3.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0f%28x%29%EF%BC%9Dx%26%23179%3B%EF%BC%8Bax%26%23178%3B%EF%BC%8Bbx%EF%BC%8Bc.%E8%BF%87%E6%9B%B2%E7%BA%BFy%EF%BC%9Df%28x%29%E4%B8%8A%E7%9A%84%E7%82%B9p%281.f%281%29%29%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAy%EF%BC%9D3x%EF%BC%8B1.%E8%8B%A5%E5%87%BD%E6%95%B0y%EF%BC%9Df%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-2%2C1%5D%E4%B8%8A%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%2C%E6%B1%82%E5%AE%9E%E6%95%B0b%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4%E2%80%A6%E2%80%A6%E7%94%A8%E7%9C%8B%E5%AF%B9%E7%A7%B0%E8%BD%B4%E8%A7%A3%E6%98%AF%E5%95%A5%E6%84%8F%E6%80%9D%E6%9D%A5%E7%9D%80%E2%80%A6%E2%80%A6%E6%B1%82%E8%AF%A6%E8%A7%A3%E7%BB%99%E8%B7%AA%E4%BA%86)
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