等边三角形ABC,P是其内一点,PE//AC交AB于E,PF//AB交BC于F,PD//BC交AC于D,已知其周长为12,则PD+PE+PF=___.作DH平行于DF交BC于H,作FG平行于DE交于AB于G我不怎么理解这句话耶。
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/12 23:31:55
![等边三角形ABC,P是其内一点,PE//AC交AB于E,PF//AB交BC于F,PD//BC交AC于D,已知其周长为12,则PD+PE+PF=___.作DH平行于DF交BC于H,作FG平行于DE交于AB于G我不怎么理解这句话耶。](/uploads/image/z/7007641-25-1.jpg?t=%E7%AD%89%E8%BE%B9%E4%B8%89%E8%A7%92%E5%BD%A2ABC%2CP%E6%98%AF%E5%85%B6%E5%86%85%E4%B8%80%E7%82%B9%2CPE%2F%2FAC%E4%BA%A4AB%E4%BA%8EE%2CPF%2F%2FAB%E4%BA%A4BC%E4%BA%8EF%2CPD%2F%2FBC%E4%BA%A4AC%E4%BA%8ED%2C%E5%B7%B2%E7%9F%A5%E5%85%B6%E5%91%A8%E9%95%BF%E4%B8%BA12%2C%E5%88%99PD%2BPE%2BPF%3D___.%E4%BD%9CDH%E5%B9%B3%E8%A1%8C%E4%BA%8EDF%E4%BA%A4BC%E4%BA%8EH%2C%E4%BD%9CFG%E5%B9%B3%E8%A1%8C%E4%BA%8EDE%E4%BA%A4%E4%BA%8EAB%E4%BA%8EG%E6%88%91%E4%B8%8D%E6%80%8E%E4%B9%88%E7%90%86%E8%A7%A3%E8%BF%99%E5%8F%A5%E8%AF%9D%E8%80%B6%E3%80%82)
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