设x-y+1=0,求d=根号下x2+y2+6x-10y+34加上根号下x2+y2-4x-30y+229的最小值我看过一些答案,不明白为什么d表示直线上的点到两圆心的距离?
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 09:02:26
![设x-y+1=0,求d=根号下x2+y2+6x-10y+34加上根号下x2+y2-4x-30y+229的最小值我看过一些答案,不明白为什么d表示直线上的点到两圆心的距离?](/uploads/image/z/7016290-34-0.jpg?t=%E8%AE%BEx-y%2B1%3D0%2C%E6%B1%82d%3D%E6%A0%B9%E5%8F%B7%E4%B8%8Bx2%2By2%2B6x-10y%2B34%E5%8A%A0%E4%B8%8A%E6%A0%B9%E5%8F%B7%E4%B8%8Bx2%2By2-4x-30y%2B229%E7%9A%84%E6%9C%80%E5%B0%8F%E5%80%BC%E6%88%91%E7%9C%8B%E8%BF%87%E4%B8%80%E4%BA%9B%E7%AD%94%E6%A1%88%2C%E4%B8%8D%E6%98%8E%E7%99%BD%E4%B8%BA%E4%BB%80%E4%B9%88d%E8%A1%A8%E7%A4%BA%E7%9B%B4%E7%BA%BF%E4%B8%8A%E7%9A%84%E7%82%B9%E5%88%B0%E4%B8%A4%E5%9C%86%E5%BF%83%E7%9A%84%E8%B7%9D%E7%A6%BB%3F)
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