求y=(4x∧2-1)÷(x∧2-1)的n阶导数,
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求y=(4x∧2-1)÷(x∧2-1)的n阶导数,
求y=(4x∧2-1)÷(x∧2-1)的n阶导数,
求y=(4x∧2-1)÷(x∧2-1)的n阶导数,
先化简
y=4+3/(x^2-1)=4+3/2[1/(x-1)+1/(x+1)]
下面就简单了:
y(n)=3/2(-1)^n*(n-1)![1/(x-1)^(n+1)+1/(x+1)^(n+1)]
Y = 1 /(X ^ 2-1)= 1 /(X +1)(X-1)= 0.5 [1 /(X-1)-1 /(X +1)] 结果求y = 1 /(X ^ 2-1)衍生物n阶,分别,相当于寻求Y = 0.5 /(X-1)和y = 0.5 /(X +1)n阶导数,然后做穷人的然后两个公式可以直接使用简单的我希望学业进步
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