若(a+m)(a-1)=a²-3a+n,则m+n=
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若(a+m)(a-1)=a²-3a+n,则m+n=
若(a+m)(a-1)=a²-3a+n,则m+n=
若(a+m)(a-1)=a²-3a+n,则m+n=
将(a+m)(a-1)展开得到
(a+m)(a-1)=a²-(1-m)a-m=a²-3a+n
通过对比系数可以得到:
1-m=3,-m=n
很显然m+n=0