当x^2(x^2+2(y)^2)=y^2(6(x)^2+5(y)^2),求(x-3(xy)^2+2y)/(x+(xy)^2-6y)
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当x^2(x^2+2(y)^2)=y^2(6(x)^2+5(y)^2),求(x-3(xy)^2+2y)/(x+(xy)^2-6y)
当x^2(x^2+2(y)^2)=y^2(6(x)^2+5(y)^2),
求(x-3(xy)^2+2y)/(x+(xy)^2-6y)
当x^2(x^2+2(y)^2)=y^2(6(x)^2+5(y)^2),求(x-3(xy)^2+2y)/(x+(xy)^2-6y)
问题中的分数线上下的次数应该是统一的2次吧?
整理已知等式可以得到 x^4-4(xy)^2-5y^4=0
十字相乘法 因式分解得到x^2=5y^2
之后分子分母上下同时除以y^2