已知A={a+2,(a+1)²,a²+3a+3},若1∈A,则实数a构成的集合B的元素个数是我算出来a=-1或0或-2或-1或-2约完后剩了3个,0,-1,-2可答案上是一个,
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![已知A={a+2,(a+1)²,a²+3a+3},若1∈A,则实数a构成的集合B的元素个数是我算出来a=-1或0或-2或-1或-2约完后剩了3个,0,-1,-2可答案上是一个,](/uploads/image/z/7079263-7-3.jpg?t=%E5%B7%B2%E7%9F%A5A%EF%BC%9D%7Ba%EF%BC%8B2%2C%28a%EF%BC%8B1%29%26%23178%3B%2Ca%26%23178%3B%EF%BC%8B3a%EF%BC%8B3%7D%2C%E8%8B%A51%E2%88%88A%2C%E5%88%99%E5%AE%9E%E6%95%B0a%E6%9E%84%E6%88%90%E7%9A%84%E9%9B%86%E5%90%88B%E7%9A%84%E5%85%83%E7%B4%A0%E4%B8%AA%E6%95%B0%E6%98%AF%E6%88%91%E7%AE%97%E5%87%BA%E6%9D%A5a%EF%BC%9D-1%E6%88%960%E6%88%96-2%E6%88%96-1%E6%88%96-2%E7%BA%A6%E5%AE%8C%E5%90%8E%E5%89%A9%E4%BA%863%E4%B8%AA%2C0%2C-1%2C-2%E5%8F%AF%E7%AD%94%E6%A1%88%E4%B8%8A%E6%98%AF%E4%B8%80%E4%B8%AA%2C)
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