(x+y)²=1,(x-y)²=11,求x+y与xy的值

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(x+y)²=1,(x-y)²=11,求x+y与xy的值
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(x+y)²=1,(x-y)²=11,求x+y与xy的值
(x+y)²=1,(x-y)²=11,求x+y与xy的值

(x+y)²=1,(x-y)²=11,求x+y与xy的值
问题:(x+y)²=1,(x-y)²=11,求x+y与xy的值.
  解析:(x+y)²=1,x²+2xy+y²=1
(x-y)²=11,x²-2xy+y²=11
两式相减:4xy=-10,得xy=-5/2
(x+y)²=1,开方得:x+y=1或-1