SINα=2/3 则COS(π-2α)=?
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SINα=2/3 则COS(π-2α)=?
SINα=2/3 则COS(π-2α)=?
SINα=2/3 则COS(π-2α)=?
COS(π-2α)=2(sina)^2-1
SINα=2/3 COS(π-2α)=-1/9
sinα=2/3
cos(π-2α)=-cos2α=-[1-2(sinα)^2]=-1+2(sinα)^2=-1+2*(2/3)^2=-1+8/9=-1/9
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