y=log2(x^2+1)的单调区间 y=log1/2(4x-x^2)^2的单调递减递增区间y=log2(x^2+1)的单调区间y=log1/2(4x-x^2)^2的单调递减递增区间
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 10:49:08
![y=log2(x^2+1)的单调区间 y=log1/2(4x-x^2)^2的单调递减递增区间y=log2(x^2+1)的单调区间y=log1/2(4x-x^2)^2的单调递减递增区间](/uploads/image/z/7080834-66-4.jpg?t=y%3Dlog2%28x%5E2%2B1%29%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4+y%3Dlog1%2F2%284x-x%5E2%29%5E2%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4y%3Dlog2%28x%5E2%2B1%29%E7%9A%84%E5%8D%95%E8%B0%83%E5%8C%BA%E9%97%B4y%3Dlog1%2F2%284x-x%5E2%29%5E2%E7%9A%84%E5%8D%95%E8%B0%83%E9%80%92%E5%87%8F%E9%80%92%E5%A2%9E%E5%8C%BA%E9%97%B4)
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y=log2(x^2+1)的单调区间 y=log1/2(4x-x^2)^2的单调递减递增区间y=log2(x^2+1)的单调区间y=log1/2(4x-x^2)^2的单调递减递增区间
y=log2(x^2+1)的单调区间 y=log1/2(4x-x^2)^2的单调递减递增区间
y=log2(x^2+1)的单调区间
y=log1/2(4x-x^2)^2的单调递减递增区间
y=log2(x^2+1)的单调区间 y=log1/2(4x-x^2)^2的单调递减递增区间y=log2(x^2+1)的单调区间y=log1/2(4x-x^2)^2的单调递减递增区间
(1)运用复合函数单调性的处理方法:同曾异减
y=log2(x^2+1) 以2为底的对数函数为增函数,x^2+1的增【0,无穷)也是原函数的增区间,同理原函数的减区间为(负无穷,0)
下面的题 也可以用这种方法来做.