根号2sin(πx/8+π/4)+根号2sin(πx/8+3π/4)化简

根号2sin(x+π/4)化简 根号2sin(πx/8+π/4)+根号2sin(πx/8+3π/4)化简 根号下2/4sin(π/4-x)+根号下6/4cos(π/4-x) f(x)=根号2sin(2x+π/4)+2-根号2对称轴方程 化简sin(2x+π/3)-（根号3）sin²x+sinxcosx+(根号3)/2 求证sinx-cosx=根号2sin(x-π/4) 解三角方程:根号2sin(x+π/4)=1 根号2*sin(π/4-x)+根号6*sin（π/4+x）的化简结果是 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 f(x)=2sinπ/4cosπ/4- 2根号3sin^2π/4+根号3 f(x)=2sinπ/4cosπ/4-2根号3sin^2π/4+根号3 根号2/4sin（π/4-x）+根号6/4cos（π/4-x） 化简根号2/4就是四分之根号二 化简根号2sin(π/3-x)+根号6cos(π/3-x) 利用和（差）公式化简根号2/4sin(π/4-x)+根号6/4cos(π/4-x) 求根号2/4sin(π/4-x)+根号6/4cos(π/4-x)的化简, f(x)=2sin^2(π/4+x)+根号3(sin^2x+cos^2x)f(x)=2sin^2(π/4+x)+根号3(sin^2x-cos^2x) 符号打错了 已知x+y=根号2sin(a+π/4),x-y=根号2sin(a-π/4),求证x^2+y^2=1 已知x+y=根号2sin(a+π/4),x-y=根号2sin(a-π/4),求证x^2+y^2=1