已知x+y-2+0,求(x^-y^)^-8(x^+y^)的值ladies and 乡亲们啊,救救我啊,就差一题了~题目打错了已知x+y-2=0,求(x^-y^)^-8(x^+y^)的值
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已知x+y-2+0,求(x^-y^)^-8(x^+y^)的值ladies and 乡亲们啊,救救我啊,就差一题了~题目打错了已知x+y-2=0,求(x^-y^)^-8(x^+y^)的值
已知x+y-2+0,求(x^-y^)^-8(x^+y^)的值
ladies and 乡亲们啊,救救我啊,就差一题了~
题目打错了已知x+y-2=0,求(x^-y^)^-8(x^+y^)的值
已知x+y-2+0,求(x^-y^)^-8(x^+y^)的值ladies and 乡亲们啊,救救我啊,就差一题了~题目打错了已知x+y-2=0,求(x^-y^)^-8(x^+y^)的值
如果你的上标是2次方的话 可以这样做
x+y-2=0可以推出x+y=2
(X^-Y^)^-8(X^+Y^)=[(X+Y)(X-Y)]^-8(X^+Y^)
=4(X-Y)^-8(X^+Y^)
=4X^-8XY+4Y^-8X^-8Y^
=-4X^-8XY-4Y^
=-4(X+Y)^
=-4*4
=-16
应该是这样的 做这类题目的要点在于先求出X与Y的关系表达式,然后进行化简,最后一定可以化成一个简单的式子 然后代入就可以了
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