已知A=√x²,B=lx-1l (1)若x≥0,化简A+B (2)若x<1,化简A+B
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已知A=√x²,B=lx-1l (1)若x≥0,化简A+B (2)若x<1,化简A+B
已知A=√x²,B=lx-1l (1)若x≥0,化简A+B (2)若x<1,化简A+B
已知A=√x²,B=lx-1l (1)若x≥0,化简A+B (2)若x<1,化简A+B
A=√x²=|x| , B=|x-1|
(1):若x≥0,分别讨论:
当0≤x≤1时
A+B=|x|+|x-1|
=x-(x-1)
=x-x+1
=1
当x﹥1时
A+B=|x|+|x-1|
=x+x-1
=2x-1
(2):若x﹤1,分别讨论:
当0≤x﹤1时
A+B=|x|+|x-1|
=x-(x-1)
=x-x+1
=1
当x﹤0时
A+B=|x|+|x-1|
=-x-(x-1)
=-x-x+1
=-2x+1