f(x)=1/3x3+1/2ax2+ax-2.a∈R.若函数f(x)在(-∞,+∞)上为单调递增函数,求a的取值范围
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/30 10:38:46
![f(x)=1/3x3+1/2ax2+ax-2.a∈R.若函数f(x)在(-∞,+∞)上为单调递增函数,求a的取值范围](/uploads/image/z/7116340-4-0.jpg?t=f%28x%29%3D1%2F3x3%2B1%2F2ax2%2Bax-2.a%E2%88%88R.%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E5%9C%A8%28-%E2%88%9E%2C%2B%E2%88%9E%29%E4%B8%8A%E4%B8%BA%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%E5%87%BD%E6%95%B0%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
x)KӨд57067J0N5K|{Ϧn z:gy:@BɎ';v=bCˆIO̓y)Ӟ6yt"}X_`gCG?=]i6{^i[K;";{8efG2v`иJG]mtMm@ #ޏ
f(x)=1/3x3+1/2ax2+ax-2.a∈R.若函数f(x)在(-∞,+∞)上为单调递增函数,求a的取值范围
f(x)=1/3x3+1/2ax2+ax-2.a∈R.若函数f(x)在(-∞,+∞)上为单调递增函数,求a的取值范围
f(x)=1/3x3+1/2ax2+ax-2.a∈R.若函数f(x)在(-∞,+∞)上为单调递增函数,求a的取值范围
对其求导得y=x^2+ax+a
因为函数f(x)是增函数,所以y>0
所以对y,⊿=a^2-4a