八下分式方程(x²-1分之2)+(x+1分之1)=1(x分之3)+(x-1分之3)=x²-x分之x+5(x分之3)-(1-x分之6)-(x(1-x)分之x+5)=0
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/05 14:30:01
![八下分式方程(x²-1分之2)+(x+1分之1)=1(x分之3)+(x-1分之3)=x²-x分之x+5(x分之3)-(1-x分之6)-(x(1-x)分之x+5)=0](/uploads/image/z/7123720-40-0.jpg?t=%E5%85%AB%E4%B8%8B%E5%88%86%E5%BC%8F%E6%96%B9%E7%A8%8B%EF%BC%88x%26%23178%3B-1%E5%88%86%E4%B9%8B2%EF%BC%89%2B%EF%BC%88x%2B1%E5%88%86%E4%B9%8B1%EF%BC%89%3D1%EF%BC%88x%E5%88%86%E4%B9%8B3%EF%BC%89%2B%EF%BC%88x-1%E5%88%86%E4%B9%8B3%EF%BC%89%3Dx%26%23178%3B-x%E5%88%86%E4%B9%8Bx%2B5%EF%BC%88x%E5%88%86%E4%B9%8B3%EF%BC%89-%EF%BC%881-x%E5%88%86%E4%B9%8B6%EF%BC%89-%EF%BC%88x%EF%BC%881-x%EF%BC%89%E5%88%86%E4%B9%8Bx%2B5%EF%BC%89%3D0)
xՑOO0
-k;ݸ00&DOLL8xd?r+K0ߧ7fwӯ?KOp{|:U:fPfdq^'2[^=Qdz5{d؉v@,vlf˿zu'l5K'[/ęRґn9v# qu
八下分式方程(x²-1分之2)+(x+1分之1)=1(x分之3)+(x-1分之3)=x²-x分之x+5(x分之3)-(1-x分之6)-(x(1-x)分之x+5)=0
八下分式方程
(x²-1分之2)+(x+1分之1)=1
(x分之3)+(x-1分之3)=x²-x分之x+5
(x分之3)-(1-x分之6)-(x(1-x)分之x+5)=0
八下分式方程(x²-1分之2)+(x+1分之1)=1(x分之3)+(x-1分之3)=x²-x分之x+5(x分之3)-(1-x分之6)-(x(1-x)分之x+5)=0
题目貌似有问题