A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.

A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.

A paintball with a mass of 0.15kg is fired from a paintball gun that has a mass of 5.5 kg.The paintball leaves the gun with a velocity of 45 m/s [N] having accelerated for 0.10 s.Calculate the acceleration and the final velocity of the paintball gun.
The original velocity is 0,so the a=v/t=450m/s`2
Acoording to the momentum theorem:m1×v1=m2×v2
so v2=0.15×45/5.5=1.23m/s

0.15kg的彩球，从质量为5.5kg的枪射出，加速0.10s后初速度是45m/s，计算加速度和枪的最终速度是多少。
这个可能是要用到动量定理：
m1 *V1=m2*V2 5.5* X=45*0.15 X=1.22
a=V/t= 45/0.10=450...

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0.15kg的彩球，从质量为5.5kg的枪射出，加速0.10s后初速度是45m/s，计算加速度和枪的最终速度是多少。
这个可能是要用到动量定理：
m1 *V1=m2*V2 5.5* X=45*0.15 X=1.22
a=V/t= 45/0.10=450
猜的，不知道对不对

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