已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012）1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/18 09:47:10
已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012）1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)
xP0|FH-.K&7%1arp0,q ~-0ﾻ^.N~LH2]n3i.n_6-.h+8i!%@saz aPߛb0 \)H[[<<

已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012）1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)
已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012）
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)

已知|ab-2|与|b-1|互为相反数,试求代数式1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012）1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)
|ab-2|+|b-1|=0
b-1=0 b=1
ab=2 a=2/b=2
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+.+1/(a+2012)(b+2012)
=1/1x2+1/2x3+1/3x4+...+1/2013x2014
=1-1/2+1/2-1/3+1/3-1/4+...+1/2013-1/2014
=1-1/2014
=2013/2014