x+y+z=6 -x+y+z=4 x-y+z=2 解三元一次方程

(x+y-z)(x-y+z)= X+Y+Z=? x/y=(x+z)/(y+z)y/z=(x+y)/(x+z) 已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=? x+y+z=4x-5y=y-x+6z,xyz不等0,x:y:z=? (y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值 解方程 x(x+y+z)=6 y(x+y+z)=12 z(x+y+z)=18 解方程组{x(x+y+z)=6,y(x+y+z)=12,z(x+y+z)=18 解方程组：{x(x+y+z)=6 {y(x+y+z)=9 {z(x+y+z)=10 z+=x>y?++x: x+y/2=z+x/3=y+z/4 x+y+z=27 x-4y+z=-302x+y-z=18x--y-z=7 14x+4y+z=200,x+y+z=100求解x,y,z x+2y=3x+2z=4y+z 求x:y:z 已知3X=4X,5Y=6Z求X+Y：Y+Z 若x,y,z成等差数列,则(z-x)^2-4(x-y)(y-z)= (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z x=y; y=z; z=x/y