若|X+Y-4|+(XY-1)^2=0,则X^2+Y^2=__________
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若|X+Y-4|+(XY-1)^2=0,则X^2+Y^2=__________
若|X+Y-4|+(XY-1)^2=0,则X^2+Y^2=__________
若|X+Y-4|+(XY-1)^2=0,则X^2+Y^2=__________
|X+Y-4|+(XY-1)^2=0
得到X+Y=4
XY=1
X^2+Y^2=(X+Y)^2-2XY=16-2=14
等于14
x^2+y^2=(x+y)^2-2xy=16-2=14
X+Y-4=0
x+y=4
XY-1=0
xy=1
(x+y)^2=x^2+2xy+y^2=16
x^2+y^2=16-2xy=16-2=14
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