若tana=2,则sin^2a-4sina*cosa+2= ⊙ o ⊙ )
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/08 09:51:44
![若tana=2,则sin^2a-4sina*cosa+2= ⊙ o ⊙ )](/uploads/image/z/7174046-38-6.jpg?t=%E8%8B%A5tana%3D2%2C%E5%88%99sin%5E2a-4sina%2Acosa%2B2%3D+%E2%8A%99+o+%E2%8A%99+%EF%BC%89)
x){ѽ$1/Hi̼8D] _mdkB>|&Hd=v6 RRck hik[C/~o:HVH4PHSTS}1
BC.\
شg
Ov/T[C%O?RkF 1s G
若tana=2,则sin^2a-4sina*cosa+2= ⊙ o ⊙ )
若tana=2,则sin^2a-4sina*cosa+2= ⊙ o ⊙ )
若tana=2,则sin^2a-4sina*cosa+2= ⊙ o ⊙ )
tana=sina/cosa=2
(sina)^2+(cosa)^2=1
解得sina=(2*5^1/2)/5,cosa=(5^1/2)/5或sina=-(2*5^1/2)/5,cosa=-(5^1/2)/5
所以sin^2a=4/5,sina*cosa=1/5
所以原式=4/5-4*1/5+2=2
若tana=2则sin^2a+sinacosa
若tana=2,则sin²a=
k=(2sin^2a+sin2a)/(1+tana) 则sin(a-3.14/4)的值
tana=2 sin平方a=
若tana=2,则【sin^2a-cos^2a】/[2sin^2a+cos^2a]=
已知tana=2,则[sin(π/2+a)-cos(π-a)]/[sin(π/2-a)-sin(π-a)]=?
若tana=1/3,则sin^3 a+2cos^ 3 a/sin^3 a-2cos^3 a
若tana=2,则1/4sin^2a+1/2sin2a=
若tana=-2,则1/4sin^2a+2/5cos2a=
若tanA=2,则1/4Sin^A+1/2Sin2A=
已知tana=2,则2sin^a+sinacosa
tana=2则 sin²a+sinacosa=
sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=?
sin(a+b)=1/2,sin(a-b)=1/3,则tana/tanb=?
已知tana=3,则sin平方a=sin平方2a的值为?
已知sin(a+x)=1/2,sin(a-x)=1/3,则tana/tanx
tanA=2 求(sin^2 A+ sinAcosA)/(tanA+1+sin^2 A) 急 .
已知tana=2,则(sin^3a+cosa)/(sin^3a+sina)的值为?