设cos^2(x-y)-cos^2(x+y)=1/2,(1+cos2x)*(1+cos2y)=1/3,则tanxtany=?
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![设cos^2(x-y)-cos^2(x+y)=1/2,(1+cos2x)*(1+cos2y)=1/3,则tanxtany=?](/uploads/image/z/7201986-42-6.jpg?t=%E8%AE%BEcos%5E2%28x-y%29-cos%5E2%28x%2By%29%3D1%2F2%2C%281%2Bcos2x%29%2A%281%2Bcos2y%29%3D1%2F3%2C%E5%88%99tanxtany%3D%3F)
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