lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=(300^2+300^2)^(1/2);(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC
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![lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=(300^2+300^2)^(1/2);(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC](/uploads/image/z/7203104-8-4.jpg?t=lingo%E6%B1%82%E5%8A%A9min%3Dtob%2Btbc%2Btac%3BAM%3D%28%28300-80%29%5E2%2B%28300-210%29%5E2%29%5E%281%2F2%29%3BOM%3D%2880%5E2%2B210%5E2%29%5E%281%2F2%29%3BAC%3D%28AM%5E2-R%5E2%29%5E%281%2F2%29%3BOB%3D%28OM%5E2-R%5E2%29%5E%281%2F2%29%3Btob%3DOB%2F5%3Btac%3DAC%2F5%3BR%2FAM%3D%40cos%28AMC%29%3BR%2FOM%3D%40cos%28OMB%29%3BAO%3D%28300%5E2%2B300%5E2%29%5E%281%2F2%29%3B%28AM%5E2%2BOM%5E2-AO%5E2%29%2F%282%2AAM%2AOM%29%3D%40cos%28AMO%29%3BBMC%3D2%2A%40acos%28-1%29-AMC)
lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=(300^2+300^2)^(1/2);(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC
lingo求助
min=tob+tbc+tac;
AM=((300-80)^2+(300-210)^2)^(1/2);
OM=(80^2+210^2)^(1/2);
AC=(AM^2-R^2)^(1/2);
OB=(OM^2-R^2)^(1/2);
tob=OB/5;
tac=AC/5;
R/AM=@cos(AMC);
R/OM=@cos(OMB);
AO=(300^2+300^2)^(1/2);
(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);
BMC=2*@acos(-1)-AMC-OMB-AMO;
BC=R*BMC;
v=5/(1+@exp(10-0.1*R^2));
tbc=BC/v;
R>=10;
R
lingo求助min=tob+tbc+tac;AM=((300-80)^2+(300-210)^2)^(1/2);OM=(80^2+210^2)^(1/2);AC=(AM^2-R^2)^(1/2);OB=(OM^2-R^2)^(1/2);tob=OB/5;tac=AC/5;R/AM=@cos(AMC);R/OM=@cos(OMB);AO=(300^2+300^2)^(1/2);(AM^2+OM^2-AO^2)/(2*AM*OM)=@cos(AMO);BMC=2*@acos(-1)-AMC
调试(DEBUG)命令只对线性模型,且模型不可行或无界时才能使用 你的角度才是变量,使用的是三角函数 不是线性函数
最后一句后面加分号