已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y .,求实数m的取值笵围.已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y+1=0 ,0
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已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y .,求实数m的取值笵围.已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y+1=0 ,0
已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y .,求实数m的取值笵围.
已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y+1=0 ,0
已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y .,求实数m的取值笵围.已知集合A={(x,y) | x^2+mx-y+2=0} ,B={(x,y) | x-y+1=0 ,0
要A交B不为空集,则要方程 x^2+mx-(x+1)+2=0在[0,2]上有解
方程化为[x+(m-1)/2]^2+1-(m-1)^2/4=0,设函数y=[x+(m-1)/2]^2+1-(m-1)^2/4【结合图形】
当-(m-1)/2<=0,即m>=1时,要在[0,2]上有解则要满足y(0)<=0且y(2)>=0,明显y(0)=1>0不合题意;
当-(m-1)/2>=2,即m<=-3时,要在[0,2]上有解则要满足y(0)>=0且y(2)<=0,结合m<=-3有,解为m<=-3;
当0<-(m-1)/2<2,即-3