已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
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已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
左右相加 化简之后 |√x-√3|+|x-3|=-(a+b) |√x-√3|+|x-3|≥0 -(a+b)≤0 所以x=3 a=b=0 带回去计算 得y=1 (2^x+y)+(2^a+b)=8+1+1+0=10
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