已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
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![已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是](/uploads/image/z/7205100-60-0.jpg?t=%E5%B7%B2%E7%9F%A5%E5%AE%9E%E6%95%B0a.b.x.y%E6%BB%A1%E8%B6%B3y%2B%7C%E2%88%9Ax-%E2%88%9A3%7C%3D1-a%2C%7Cx-3%7C%3Dy-1-b%2C%E5%88%99%282%5Ex%2By%29%2B%282%5Ea%2Bb%29%E7%9A%84%E5%80%BC%E6%98%AF)
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已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
已知实数a.b.x.y满足y+|√x-√3|=1-a,|x-3|=y-1-b,则(2^x+y)+(2^a+b)的值是
左右相加 化简之后 |√x-√3|+|x-3|=-(a+b) |√x-√3|+|x-3|≥0 -(a+b)≤0 所以x=3 a=b=0 带回去计算 得y=1 (2^x+y)+(2^a+b)=8+1+1+0=10
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