如图,在RT△ABC中,∠BAC=90°,AD垂直BC于点D,BE平分∠ABC交AD于点F,交AC于点E,若EG⊥BC于点G连接FG,求证AFGE是菱形
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![如图,在RT△ABC中,∠BAC=90°,AD垂直BC于点D,BE平分∠ABC交AD于点F,交AC于点E,若EG⊥BC于点G连接FG,求证AFGE是菱形](/uploads/image/z/7228215-63-5.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8RT%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0BAC%3D90%C2%B0%2CAD%E5%9E%82%E7%9B%B4BC%E4%BA%8E%E7%82%B9D%2CBE%E5%B9%B3%E5%88%86%E2%88%A0ABC%E4%BA%A4AD%E4%BA%8E%E7%82%B9F%2C%E4%BA%A4AC%E4%BA%8E%E7%82%B9E%2C%E8%8B%A5EG%E2%8A%A5BC%E4%BA%8E%E7%82%B9G%E8%BF%9E%E6%8E%A5FG%2C%E6%B1%82%E8%AF%81AFGE%E6%98%AF%E8%8F%B1%E5%BD%A2)
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