已知圆C:(x-2)²+y²=5及直线l:x-y+b=0,当直线l被圆C截得的弦长为2√3时,b的值为圆C:(x-2)²+(y-1²)=5
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![已知圆C:(x-2)²+y²=5及直线l:x-y+b=0,当直线l被圆C截得的弦长为2√3时,b的值为圆C:(x-2)²+(y-1²)=5](/uploads/image/z/7240104-0-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%9C%86C%3A%28x-2%29%26%23178%3B%2By%26%23178%3B%3D5%E5%8F%8A%E7%9B%B4%E7%BA%BFl%3Ax-y%2Bb%3D0%2C%E5%BD%93%E7%9B%B4%E7%BA%BFl%E8%A2%AB%E5%9C%86C%E6%88%AA%E5%BE%97%E7%9A%84%E5%BC%A6%E9%95%BF%E4%B8%BA2%E2%88%9A3%E6%97%B6%2Cb%E7%9A%84%E5%80%BC%E4%B8%BA%E5%9C%86C%3A%28x-2%29%26%23178%3B%2B%EF%BC%88y-1%26%23178%3B%EF%BC%89%3D5)
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已知圆C:(x-2)²+y²=5及直线l:x-y+b=0,当直线l被圆C截得的弦长为2√3时,b的值为圆C:(x-2)²+(y-1²)=5
已知圆C:(x-2)²+y²=5及直线l:x-y+b=0,当直线l被圆C截得的弦长为2√3时,b的值为
圆C:(x-2)²+(y-1²)=5
已知圆C:(x-2)²+y²=5及直线l:x-y+b=0,当直线l被圆C截得的弦长为2√3时,b的值为圆C:(x-2)²+(y-1²)=5
圆心是(2,0),所以到直线的距离为|2+b|/√2 且半径为√5,则(2+b)^2/2+3=5 解得b=0或-4