作业帮已知log2（log8^m)=log8(log2^m),求log2^m的平方
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已知log2（log8^m)=log8(log2^m),求log2^m的平方
已知log2（log8^m)=log8(log2^m),求log2^m的平方
已知log2（log8^m)=log8(log2^m),求log2^m的平方
log2（log8^m)=log8(log2^m),
log2（1/3log2^m)=log8(log2^m)=1/3log2(log2^m)
1/3log2^m=(log2^m)^1/3
[1/27(log2^m)^2-1][log2^m]=0
(log2^m)^2=27或0
已知log2（log8^m)=log8(log2^m),求log2^m的平方
若log2(log8 m)=log8(log2 m),则(log2 m)^2
(log8 9/log2 3)=?
已知log2^3=a.则log8^3= log8^9=
log8(9)*log2(3)
已知log8^9=a,log2^5=b,则lg3=?
求(log2^3+log8^9)
log4 243 - log8 729=?log4 12 - log2 6=?
log8 4=?2^(log2 3-2)=?
log2 3=a,则log8 √3=_______
log8的9次方/log2的3次方=
已知log8 9=a ,log2 5=b,则lg3等于什么(用a,b表示)
log8^9/log2^3的值是
log8的27除以log2的3
已知log8 9=m,log3 5=n,求log5 12
已知 a=log2 3 ,那么 log8 3 — log2 6 用 a 怎么表示?(我个人算得等于 — 4 ,不知是否正确.）希望各位赐教、.
log4 8-log8 4=?
log8(9)*log27(32)=?