初二二次根式题 2008x^3=2009y^3=2010z^3,且xyz>0又:三次根号(2008x^3+2009y^3+2010z^3)(根号包括了此三次三项多项式)=三次根号2008+三次根号2009-三次根号2010 ,求x分之1 +y分之1-z分之1?
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![初二二次根式题 2008x^3=2009y^3=2010z^3,且xyz>0又:三次根号(2008x^3+2009y^3+2010z^3)(根号包括了此三次三项多项式)=三次根号2008+三次根号2009-三次根号2010 ,求x分之1 +y分之1-z分之1?](/uploads/image/z/7286498-26-8.jpg?t=%E5%88%9D%E4%BA%8C%E4%BA%8C%E6%AC%A1%E6%A0%B9%E5%BC%8F%E9%A2%98+2008x%5E3%3D2009y%5E3%3D2010z%5E3%2C%E4%B8%94xyz%3E0%E5%8F%88%EF%BC%9A%E4%B8%89%E6%AC%A1%E6%A0%B9%E5%8F%B7%EF%BC%882008x%5E3%2B2009y%5E3%2B2010z%5E3%EF%BC%89%EF%BC%88%E6%A0%B9%E5%8F%B7%E5%8C%85%E6%8B%AC%E4%BA%86%E6%AD%A4%E4%B8%89%E6%AC%A1%E4%B8%89%E9%A1%B9%E5%A4%9A%E9%A1%B9%E5%BC%8F%EF%BC%89%3D%E4%B8%89%E6%AC%A1%E6%A0%B9%E5%8F%B72008%2B%E4%B8%89%E6%AC%A1%E6%A0%B9%E5%8F%B72009-%E4%B8%89%E6%AC%A1%E6%A0%B9%E5%8F%B72010+%2C%E6%B1%82x%E5%88%86%E4%B9%8B1+%2By%E5%88%86%E4%B9%8B1-z%E5%88%86%E4%B9%8B1%3F)
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