数列{an}中,a1=1,a2=3 a(n+2)+4a(n+1)-5an=0 n属于N* 求数列的通项公式数列{an}中,a1=1,a2=3 a(n+2)+4a(n+1)-5an=0 n属于N* 求数列的通项公式其中 n+2 ,n+1 ,n 都为下标
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![数列{an}中,a1=1,a2=3 a(n+2)+4a(n+1)-5an=0 n属于N* 求数列的通项公式数列{an}中,a1=1,a2=3 a(n+2)+4a(n+1)-5an=0 n属于N* 求数列的通项公式其中 n+2 ,n+1 ,n 都为下标](/uploads/image/z/7290089-17-9.jpg?t=%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%AD%2Ca1%3D1%2Ca2%3D3+a%28n%2B2%29%2B4a%28n%2B1%29-5an%3D0+n%E5%B1%9E%E4%BA%8EN%2A+%E6%B1%82%E6%95%B0%E5%88%97%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E6%95%B0%E5%88%97%7Ban%7D%E4%B8%AD%2Ca1%3D1%2Ca2%3D3+a%28n%2B2%29%2B4a%28n%2B1%29-5an%3D0+n%E5%B1%9E%E4%BA%8EN%2A+%E6%B1%82%E6%95%B0%E5%88%97%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%E5%85%B6%E4%B8%AD+n%2B2+%2Cn%2B1+%2Cn+%E9%83%BD%E4%B8%BA%E4%B8%8B%E6%A0%87)
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