f(x)=sin(2x+π/3 )+√3cos(2x+π/3),f(x)的周期,单调减区间为什么
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![f(x)=sin(2x+π/3 )+√3cos(2x+π/3),f(x)的周期,单调减区间为什么](/uploads/image/z/7302517-61-7.jpg?t=f%28x%29%3Dsin%282x%2B%CF%80%2F3+%29%2B%E2%88%9A3cos%282x%2B%CF%80%2F3%29%2Cf%28x%29%E7%9A%84%E5%91%A8%E6%9C%9F%2C%E5%8D%95%E8%B0%83%E5%87%8F%E5%8C%BA%E9%97%B4%E4%B8%BA%E4%BB%80%E4%B9%88)
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f(x)=sin(2x+π/3 )+√3cos(2x+π/3),f(x)的周期,单调减区间为什么
f(x)=sin(2x+π/3 )+√3cos(2x+π/3),f(x)的周期,单调减区间
为什么
f(x)=sin(2x+π/3 )+√3cos(2x+π/3),f(x)的周期,单调减区间为什么
f(x)=2sin(2x+π/3+π/3)
T=2π/2=π
单减(kπ-1/12π,kπ+5/12π)