若sinx+sin^2x=1,则cos^2x-sinX=?急...
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若sinx+sin^2x=1,则cos^2x-sinX=?急...
若sinx+sin^2x=1,则cos^2x-sinX=?
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若sinx+sin^2x=1,则cos^2x-sinX=?急...
解因为sin^2x+cos^2x=1,
sinx+sin^2x=1
所以cos^2x=sinx
所以cos^2x-sinX=sinx-sinx=0
sinx+sin^2x=1,所以,sinx=cos^2x
那么cos^2x-sinX=0
0
因为 cos^2 X + sin^2 X=1 可得 sinX=cos^2 X
sin^2x=2sinx*cosx
sinx+sin^2x=1; 则cos^2x-sinx=1-(sin^2x+sinx)=0