1:求证:函数y= 1 在区间(1,+无穷)上为单掉=调减函数.---x-1 2:讨论函数y=X②-2(2a+1)x+3在{-2,2}上的单调性.(②为次方)3:求函数y=2x+√x-1 的最大(小)值 (√为根号)4:求二次函数f(x)=x
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/17 04:26:41
![1:求证:函数y= 1 在区间(1,+无穷)上为单掉=调减函数.---x-1 2:讨论函数y=X②-2(2a+1)x+3在{-2,2}上的单调性.(②为次方)3:求函数y=2x+√x-1 的最大(小)值 (√为根号)4:求二次函数f(x)=x](/uploads/image/z/7314602-50-2.jpg?t=1%EF%BC%9A%E6%B1%82%E8%AF%81%3A%E5%87%BD%E6%95%B0y%3D+1+%E5%9C%A8%E5%8C%BA%E9%97%B4%281%2C%2B%E6%97%A0%E7%A9%B7%29%E4%B8%8A%E4%B8%BA%E5%8D%95%E6%8E%89%3D%E8%B0%83%E5%87%8F%E5%87%BD%E6%95%B0.---x-1+2%EF%BC%9A%E8%AE%A8%E8%AE%BA%E5%87%BD%E6%95%B0y%3DX%E2%91%A1-2%EF%BC%882a%2B1%EF%BC%89x%2B3%E5%9C%A8%7B-2%2C2%7D%E4%B8%8A%E7%9A%84%E5%8D%95%E8%B0%83%E6%80%A7.%EF%BC%88%E2%91%A1%E4%B8%BA%E6%AC%A1%E6%96%B9%EF%BC%893%EF%BC%9A%E6%B1%82%E5%87%BD%E6%95%B0y%3D2x%2B%E2%88%9Ax-1+%E7%9A%84%E6%9C%80%E5%A4%A7%EF%BC%88%E5%B0%8F%EF%BC%89%E5%80%BC+%EF%BC%88%E2%88%9A%E4%B8%BA%E6%A0%B9%E5%8F%B7%EF%BC%894%EF%BC%9A%E6%B1%82%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx)
xVRF-lH"Ia7<;"l4J%cc[=GݒWBN%C PTP=gƪ]_$tx$$H =8~kΚcFYEQ%A]ڵ윋D t%Ϣpj%)H>mHG85LV-ATrY1%jO` ZI(0;i`r!(/~ 9_GAdX % 3nr0R 5[[$f\3`vKi@9"T8SR \"m0!&pY~̳¨m\RtFICOJ6B֩ZٮOAݾkBy?ΩUr\nr2N"ylkS_Kgscύ./-к/CB5p$Fa Zڲ`WX̓b38β҉#Xfa.>4V+vKLz_2=x$ `4\(yHbդ<2}$DŽjsjii)0EBP)PjxrEl-j)Skuw͖:\L }I/dC\b2{<