1 2x^2-4x2 (x^2+y)^2-4x^2y^2就这么多先

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1 2x^2-4x2 (x^2+y)^2-4x^2y^2就这么多先
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1 2x^2-4x2 (x^2+y)^2-4x^2y^2就这么多先
1 2x^2-4x
2 (x^2+y)^2-4x^2y^2
就这么多先

1 2x^2-4x2 (x^2+y)^2-4x^2y^2就这么多先
2x^2-4x
＝2x(x-2)
(x^2+y^2)^2-4x^2y^2 平方差公式
=(x^2+2xy+y^2)(x^2-2xy+y^2)
=(x+y)^2 (x-y)^2

1 2x^2-4x
=2x(x-2)
2 (x^2+y)^2-4x^2y^2
=(x^2+y^2-2xy)(x^2+y^2+2xy)
=(x-y)^2*(x+y)^2

1 2x^2-4x
=2x(x-2)
2 (x^2+y)^2-4x^2y^2
=(x²+y²)²-(2xy)²
=(x²+y²+2xy)(x²+y²-2xy)
=(x+y)²(x-y)²

2x^2-4x
=2x(x-2)
(x^2+y)^2-4x^2y^2
=(x^2+y)^2-(2xy)^2
=(x^2+y+2xy)(x^2+y-2xy)

2x^2-4x=2x(x-2)
(x^2+y)^2-4x^2y^2=(x^2+y+2xy)(x^2+y-2xy)

1.x2+(1+x)2+(x+x2)22.(x+y)4+(x2-y2)2+(x-y)4 y=x+√(1-x2) y2=x2+(1-x2)+2x√(1-x2) 问几个分式化简的问题：a2-ab/b2-ab x2+x/x2-1 x2+4x/x2+8x+16 x2-2x/2y-xy y=(x2+4x+1)/x2+x+1的值域y=(x2+4x+1)/(x2+x+1)的值域注解;2为平方 y=-x2+x-2分之1 y=x2+x-2分之1 的值域?y=2x2=4x-1分之x2+2x-4 y=1-x2分之x2急啊！求解，谢谢! y=x2+2x-4的反函数y=x2+2x-4 (x 1.(x-y)(x2+xy+y2) 2.求值x2(x-1)-x(x2+x-1),其中x=2分之一 y=x2-2x+2(x y=x2-2x+1(-1 (x2-4y2)-(x+2y)因式分解 y=x2-2x+5(-1 y=x2-2x(-1 y=(x2-2x+1)/( x2+1)的值域 已知[(x2+y2)-(x-y)2+2y(x-y)]÷4y=1,求4x/4x2-y2-1/2x+y的值如图 2x(x-y)4-x2(x-y)2+xy(y-x)2 如何因式分解 函数y=(x2-4x+3)/(2x2-x-1)的值域 函数y=(x2-4x+3)/(2x2-x-1)的值域 函数y=(x2-4x+3)/(2x2-x-1)的值域需要思路