计算1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)
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计算1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)
计算1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)
计算1/(x^2-3x+2)+1/(x^2-5x+6)+1/(x^2-4x+3)
=1/(x-2)(x-1)+1/(x-2)(x-3)+1/(x-3)(x-1)
=(x-3+x-1+x-2)/(x-1)(x-2)(x-3)
=3(x-2)/(x-1)(x-2)(x-3)
=2/(x-1)(x-3)
原式=1/(x-1)(x-2)+1/(x-2)(x-3)+1/(x-1)(x-3)=[(x-3)+(x-1)+(x-2)]/(x-1)(x-2)(x-3)=3/(x-1)(x-3)
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