作业帮已知2a-b=5,求代数式[（a²+b²）+2b（a-b）-（a-b）²]÷4b的值
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/17 11:43:39
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已知2a-b=5,求代数式[（a²+b²）+2b（a-b）-（a-b）²]÷4b的值
已知2a-b=5,求代数式[（a²+b²）+2b（a-b）-（a-b）²]÷4b的值
已知2a-b=5,求代数式[（a²+b²）+2b（a-b）-（a-b）²]÷4b的值
[（a²+b²）+2b（a-b）-（a-b）²]÷4b
=(a²+b²+2ab-2b²-a²+2ab-b²)÷4b
=(4ab-2b²)÷4b
=2b(2a-b)÷4b
=(2a-b)/2
=5/2 (2分之5)
[（a²+b²）+2b（a-b）-（a-b）²]÷4b将其展开并化简得到a-b/2，a-b/2=1/2（2a-b）=2/5